Day: Feb 4, 2025

ա) sin9π/4=sinπ/4=√2/2
բ) cos19π/4=cos3π/4=-√2/2
գ) tg13π/6=tgπ/6=√3/3
դ) tg(-570)=tg(-210)=−√3/3
ե) sin(-5π/6)=-1/2
զ) cos810=cos90=0

ա) 1/2 + √2/2•√2•2= 1
բ) -1 + 2•1/2=0
գ) 2•√3/2 + 1 =√3+1
դ) √3 • (−√3/3)+0 =-1